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I onlyII only III only I and II

Answer :

BSolution :

Since is negative in the third and fourth quadrants. Cosine is negative in the second and third, so I is not necessarily true. Cosecant is 1 over sine, so where sine is negative, so is cosecant. Therefore II must be true. As for III. Absolute values are always nonnegative. The issue here is where sin x + cos x can equal 0. <br> In fact, if x is `(7pi)/(4)`, then sin `x=-(sqrt(2))/(2)` and cos `x =(sqrt(2))/(2)`, <br> `sin x + cos x = 0` when `x = (7pi)/(4)`. Transcript

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00:00 - 00:59 | if x lies between 0.25 and sin x is less than zero which of the following must be true 1 cos x is less than zero second it can take to less than zero third Motors sin x + cos x is greater than zero option 11 only option to to only option 33 only an option for 1 and 2 Now since it is given that sin x is less than zero that means X lies in the third and The Fourth quadrant that is between 5 and 25 so we have send sin x less than 0 9 x lies in the third and The Fourth |

01:00 - 01:59 | quadrant now if cos x is less than zero then cos x must lie between pi by 2 and 3 pi by 2 that is in the second and third quadrant and causes positive in the fourth copy so therefore one cause less than zero this can't be true sense cos x is positive when X lies in the fourth quadrant second thing is cosec X is less than zero we have crossed that X lesson zero we need to check whether it is |

02:00 - 02:59 | correct or not put that X is one upon sin x and y we have been already given that sin x is less than zero that means one upon sin x will also be less than zero and therefore Khushi can't explore Sahab 1102 is correct now for the third option the third choice that was given to was a lot of sin x + cos x is greater than that is it always possible to we are going to find one particular value of x line between 0 to 2pi such that sin x + cosx the whole mod is equal to zero so we can observe that when x is equal to 75 |

03:00 - 03:59 | 5410 at x is equal to 75 by 4 sin is equal to minus 1 by root 2 and cos x is equal to 1 by root 2 in this case Mod of sin x + cos x minus 1 by root 2 + 1 by root 2 is equal to zero therefore this third of you can't see through the only option that can that is possible is 2 and there for equitable to our second option to only is the correct one |

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